4(n-7)-2n(1-3n)=6n^2

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Solution for 4(n-7)-2n(1-3n)=6n^2 equation: 



4(n-7)-2n(1-3n)=6n^2

We move all terms to the left:

4(n-7)-2n(1-3n)-(6n^2)=0

determiningTheFunctionDomain
-6n^2+4(n-7)-2n(1-3n)=0

We add all the numbers together, and all the variables

-6n^2+4(n-7)-2n(-3n+1)=0

We multiply parentheses

-6n^2+6n^2+4n-2n-28=0

We add all the numbers together, and all the variables

2n-28=0

We move all terms containing n to the left, all other terms to the right

2n=28

n=28/2

n=14

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